Finite Math Examples

Find the LCM 20cd , 40a^2c^2d^4 , 15abd^3
20cd20cd , 40a2c2d440a2c2d4 , 15abd315abd3
Step 1
Since 20cd,40a2c2d4,15abd320cd,40a2c2d4,15abd3 contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 20,40,1520,40,15 then find LCM for the variable part c1,d1,a2,c2,d4,a1,b1,d3c1,d1,a2,c2,d4,a1,b1,d3.
Step 2
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 3
The prime factors for 2020 are 225225.
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Step 3.1
2020 has factors of 22 and 1010.
210210
Step 3.2
1010 has factors of 22 and 55.
225225
225225
Step 4
The prime factors for 4040 are 22252225.
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Step 4.1
4040 has factors of 22 and 2020.
220220
Step 4.2
2020 has factors of 22 and 1010.
22102210
Step 4.3
1010 has factors of 22 and 55.
22252225
22252225
Step 5
1515 has factors of 33 and 55.
3535
Step 6
The LCM of 20,40,1520,40,15 is the result of multiplying all prime factors the greatest number of times they occur in either number.
2223522235
Step 7
Multiply 2223522235.
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Step 7.1
Multiply 22 by 22.
42354235
Step 7.2
Multiply 44 by 22.
835835
Step 7.3
Multiply 88 by 33.
245245
Step 7.4
Multiply 2424 by 55.
120120
120120
Step 8
The factor for c1c1 is cc itself.
c1=cc1=c
cc occurs 11 time.
Step 9
The factor for d1d1 is dd itself.
d1=dd1=d
dd occurs 11 time.
Step 10
The factors for a2a2 are aaaa, which is aa multiplied by each other 22 times.
a2=aaa2=aa
aa occurs 22 times.
Step 11
The factors for c2c2 are cccc, which is cc multiplied by each other 22 times.
c2=ccc2=cc
cc occurs 22 times.
Step 12
The factors for d4d4 are dddddddd, which is dd multiplied by each other 44 times.
d4=ddddd4=dddd
dd occurs 44 times.
Step 13
The factor for a1a1 is aa itself.
a1=aa1=a
aa occurs 11 time.
Step 14
The factor for b1b1 is bb itself.
b1=bb1=b
bb occurs 11 time.
Step 15
The factors for d3d3 are dddddd, which is dd multiplied by each other 33 times.
d3=dddd3=ddd
dd occurs 33 times.
Step 16
The LCM of c1,d1,a2,c2,d4,a1,b1,d3c1,d1,a2,c2,d4,a1,b1,d3 is the result of multiplying all prime factors the greatest number of times they occur in either term.
ccddddaabccddddaab
Step 17
Simplify ccddddaabccddddaab.
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Step 17.1
Multiply cc by cc.
c2ddddaabc2ddddaab
Step 17.2
Multiply dd by dd by adding the exponents.
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Step 17.2.1
Move dd.
c2(dd)ddaabc2(dd)ddaab
Step 17.2.2
Multiply dd by dd.
c2d2ddaabc2d2ddaab
c2d2ddaabc2d2ddaab
Step 17.3
Multiply d2d2 by dd by adding the exponents.
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Step 17.3.1
Move dd.
c2(dd2)daabc2(dd2)daab
Step 17.3.2
Multiply dd by d2d2.
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Step 17.3.2.1
Raise dd to the power of 11.
c2(d1d2)daabc2(d1d2)daab
Step 17.3.2.2
Use the power rule aman=am+naman=am+n to combine exponents.
c2d1+2daabc2d1+2daab
c2d1+2daabc2d1+2daab
Step 17.3.3
Add 11 and 22.
c2d3daabc2d3daab
c2d3daabc2d3daab
Step 17.4
Multiply d3d3 by dd by adding the exponents.
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Step 17.4.1
Move dd.
c2(dd3)aabc2(dd3)aab
Step 17.4.2
Multiply dd by d3d3.
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Step 17.4.2.1
Raise dd to the power of 11.
c2(d1d3)aabc2(d1d3)aab
Step 17.4.2.2
Use the power rule aman=am+naman=am+n to combine exponents.
c2d1+3aabc2d1+3aab
c2d1+3aabc2d1+3aab
Step 17.4.3
Add 11 and 33.
c2d4aabc2d4aab
c2d4aabc2d4aab
Step 17.5
Multiply aa by aa by adding the exponents.
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Step 17.5.1
Move aa.
c2d4(aa)bc2d4(aa)b
Step 17.5.2
Multiply aa by aa.
c2d4a2bc2d4a2b
c2d4a2bc2d4a2b
c2d4a2bc2d4a2b
Step 18
The LCM for 20cd,40a2c2d4,15abd320cd,40a2c2d4,15abd3 is the numeric part 120120 multiplied by the variable part.
120c2d4a2b120c2d4a2b
 [x2  12  π  xdx ]  x2  12  π  xdx